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Consider the following unbalanced redox ...

Consider the following unbalanced redox reaction:
`H_(2)O+AX+BYrarrHA+OY+X_(2)B`
The oxidation number of `X` is `-2` and niether `X` nor water is involved in the redox process.
The elements(s) undergoing oxidation is`//`are

A

`A`

B

`B`

C

`Y`

D

`B` or `Y` or both

Text Solution

Verified by Experts

The correct Answer is:
D
Oxidation state of `X= -2 implies overset(+2)Aoverset(-2)X`
Oxidation state of `O= -2impliesoverset(-2+2)(OY)`
Oxidation state of `X= -2implies overset(-2xx2+4)(X_(2)B`

`e^(-)+A^(2+)rarrA^(1-)` (reduction)
`overset(+a-a)(BY)rarrB^(4+)+Y^(2+)`(oxidation)
Therefore, `B or Y` or both might have been oxidised.
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Knowledge Check

  • Consider the following unbalanced redox reaction: H_(2)O+AX+BYrarrHA+OY+X_(2)B The oxidation number of X is -2 and niether X nor water is involved in the redox process. The positive oxidation states of B and Y in BY are respectively,

    A
    `+1, -1`
    B
    `+2,-2`
    C
    `+3,-3`
    D
    All of these

  • Consider the following unbalanced redox reaction: H_(2)O+AX+BYrarrHA+OY+X_(2)B The oxidation number of X is -2 and niether X nor water is involved in the redox process. If the above reaction is balanced with smallest whole number coefficients, the sum of the stoichiometric coefficients of all the compound is

    A
    `9`
    B
    `8`
    C
    `7`
    D
    `6`

  • Consider the following redox reaction : H_(2)O + AX + BY rarr HA + YO + BX_(2) (unbalanced) It is also known that oxidation number of X is -2 and neither X nor water is involved in the redox process. (In compound BY, B is cation and consider its oxidation number lt 4 ). Answer the following question based on the information given. If the given reaction is balanced with smallest whole number coefficients, then:

    A
    Sum of stoichmetric coefficient of all the components is `8`.
    B
    Sum of stoichmetric coefficient of all the components is `9`.
    C
    Stoichiometric coefficient of `AX ` is `6`.
    D
    Stoichiometric coefficient of `HX ` is `2`.

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