Naturally occureing boron consists of two insotopes whose atomic weight are `10.01 and 11.01 ` The atomic weight of the natural boron is `10.81 ` Calkculate the precentage of e ach isotopes in natURAL BORON

Explanation

Let the percentage of the isotope be a percentage of the second isotope will be `100 - a `
`10.81 = ((a xx 10.01) + (100 - a) xx 11.01)/(100)`
On solving we get
`a = 20,(100 - a) = 80`