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Naturally occureing boron consists of ...

Naturally occureing boron consists of two insotopes whose atomic weight are `10.01 and 11.01 ` The atomic weight of the natural boron is `10.81 ` Calkculate the precentage of e ach isotopes in natURAL BORON

Text Solution

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Let the percentage of the isotope be a percentage of the second isotope will be `100 - a `
`10.81 = ((a xx 10.01) + (100 - a) xx 11.01)/(100)`
On solving we get
`a = 20,(100 - a) = 80`
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Nuturally occurring boron consists of two isotopes whese atomic weight are 10.01 and 11.01 The atomic weight of nurons is 10.81 Calculate the percentage of each isotope is natural boron

Naturally occurring Boron consists of two isotopes whose atomic masess are 10.01 and 11.01. The atomic mass of natural Boron is 10.81. Calculate the percentage of each isotope in natural Boron.

Knowledge Check

  • boron has two isotopes B-10,B-11. The average atomic mass of boron is found to be 10.80u. Calculate the percentage abundance of B^(10) isotope :-

    A
    80
    B
    20
    C
    25
    D
    75

  • In nature, ratio of isotopes Boron, ""_5B^(10) and ""_5B^(11) , is (given that atomic weight of boron is 10.81)

    A
    `81:19`
    B
    `21:44`
    C
    `19:81`
    D
    `44:21`

  • Boron has two istopes B^(10) & B^(11) whose relative abundances are 20% & 80% respectively avg.atomic weight of Boron is?

    A
    10
    B
    11
    C
    10.5
    D
    10.8

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    Naturally occurring boron contain of two isotopes, whose atomic masses are 10.01 and 11.01. the atomic mass of natural boron is 10.81. calculate the percentage of each isotope in natural boron.

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