One mole of an ideal mono-atomic gas at `27^(@)C` expands adiabatically against a constant external pressure of `1atm` from a value of `5dm^(3)` to `15dm^(3)`.calculate (a) `q` and (b) `w`.

Explanation

a. Since the process is adiabatic
b. As gas expands against a constant external pressure of 1 atm,
`w = - p DeltaV =- p (V_(f)-V_(i))`
`= (1atm) (15-5)dm^(3)`
`=- 10 atm dm^(3)`
`=- 10 xx 101.3 J (1 dm^(3) atm =101.3 J) =- 1013J`