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At equilibrium, the concentrations of N(...

At equilibrium, the concentrations of `N_(2)=3.0xx10^(-3)M, O_(2)=4.2xx10^(-3) M,` and `NO=2.8xx10^(-3) M` in a sealed vessel at `800K`. What will be `K_(c)` for the reaction
`N_(2)(g)+O_(2)(g)N_(2)(g)+O_(2)(g)hArr2NO(g)2NO(g)`

Text Solution

AI Generated Solution

To find the equilibrium constant \( K_c \) for the reaction \[ N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \] given the equilibrium concentrations of the reactants and products, we can follow these steps: ...
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At equilibrium, the concentrations of N_(2) = 3*0 xx 10^(-3) M, O_(2)= 4*2 xx 10^(-3) M and No = 2*8 xx 10^(-3) M in a sealed vessel at 800 K. What will be K_(c) for the raction N_(2) (g) + O_(2) (g) hArr 2 NO (g) ?

At 800 K in a sealed vessel for the equilibrium N_(2)(g) + O_(2) (g) hArr 2NO(g), the equilibrium concentrations of N_(2) (g), O_(2)(g) and NO(g) are respectively 0.36xx10^(-3) M, 4.41 xx 10^(-3) M and 1.4 xx 10^(-3) M. Calculate the value of K_(c) for the reaction NO(g) hArr 1//2 N_(2)(g) +1//2 O_(2) (g) at 800 K is :

Knowledge Check

  • Given the reaction between 2 gases represented by A_(2) and B_(2) to given the compound AB(g). A_(2)(g) + B_(2)(g)hArr 2AB(g) At equilibrium, the concentrtation of A_(2) = 3.0xx10^(-3) M of B_(2) = 4.2xx10^(-3) M of AB = 2.8xx10^(-3) M If the reaction takes place in a sealed vessel at 527^(@)C . then the value of K_(c) will be

    A
    `2.0`
    B
    `1.9`
    C
    `0.62`
    D
    `4.5`

  • Given the reaction between 2 gases represented by A_(2) and B_(2) to give the compound AD(g). A_(2)(g)+B_(2)(g)hArr2AB(g). At equilibrium, the concentration of A_(2)=3.0xx10^(-3)M of B_(2)=4.2xx10^(-3)M of AB=2.8xx10^(-3)M If the reaction takes place in a scaled vassel at 527^(@)C, then the value of K_(c) will be

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    `2.0`
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    C
    `0.62`
    D
    `4.5`

  • Given the reaction between 2 gases represented by A_2 and B_2, to give the compound AB_(g) A_(2(g))+B_(2(g)) Leftrightarrow 2AB_(g) At equilibrium, the concentration of A_2 =3.0 xx 10^(-3) M, of B_2= 4.2 xx 10^(-3) M", of AB "=2.8 xx 10^(-3) M If the reaction takes place in a sealed vessel at 527^@C , then the value of K_c will be

    A
    2
    B
    1.9
    C
    0.62
    D
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