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At 90^(@)C , pure water has [H(3)O^(+)] ...

At `90^(@)C` , pure water has `[H_(3)O^(+)]` as `10^(-6)` mol `L^(-1)`. What is the value of `K_(w)` at `90^(@)C` ?

A

`10^(-6)`

B

`10^(-12)`

C

`10^(-14)`

D

`10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
B
`[H_(3)O^(o+)] = 10^(-6) = [overset(Theta)OH]`
Because in pure water, `[H_(3)O^(o+)] = [overset(Theta)OH]`
`K_(w) = [H_(3)O^(o+)] = [overset(Theta)OH]`
`= 10^(-6) xx 10^(-6)`
`= 10^(-12)`
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Knowledge Check

  • At 90^(@)C , pure water has [H_(3)O^(o+)] = 10^(-6.7)mol L^(-1) . What is the value of K_(w) at 90^(@)C ?

    A
    `10^(-6)`
    B
    `10^(-12)`
    C
    `10^(-13.4)`
    D
    `10^(-6.7)`

  • At 90^(@)C , pure water has [H_(3)O^(o+)] = 10^(-6)M . What is the value of K_(w) at 90^(@)C

    A
    `10^(-6)`
    B
    `10^(-8)`
    C
    `10^(-12)`
    D
    `10^(-14)`

  • At 90^(@)C pure water has [H_(3)O^(+)] = 10^(-6) M , the value of K_(w) at this temperature will be

    A
    `10^(-6)`
    B
    `10^(-12)`
    C
    `10^(-14)`
    D
    `10^(-8)`
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