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Every atom or ion that forms an fcc unit...

Every atom or ion that forms an fcc unit cell is surrounded by

A

Six `OVs` and eight `TVs`.

B

Eight `OVs` and Six `TVs`.

C

Six `OVs` and six `TVs`.

D

Eight `OVs` and four `TVs`.

Text Solution

Verified by Experts

The correct Answer is:
A

Look at corner at atom of fcc unit cell. A corner aom can support `8` unit cell. In each cube, at a distance of `sqrt(3)a//4` from corner atom, therre is a tetrahedral void, it implied each atom is surrounded by eight tetrahedral voids. At the centre of edge, there is an octahedral void. Each corner can support six edges and hence it is surrounded by six octahedral voids.
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Knowledge Check

  • Number of atoms in fcc unit cell is

    A
    1
    B
    2
    C
    3
    D
    4
  • Only those atoms which form four covalent bonds produce a repetitive three dimensional structure using only covalent bonds, e.g., diamond structure. The latter is based on an fcc lattice where four out of the eight tetrahedral holes are occupied by carbon atoms. Every atom in this structure is surrounded tetrahedrally by four others. Germanium, silicon and grey tin also crystallize in the same way as diamond ("Given " sin 54^(@) 44'=0.8164) Total number of unit cells in one gram of such sample is

    A
    `4.95times10^(21)`
    B
    `2.01times10^(22)`
    C
    `6.27times10^(21)`
    D
    `4.95times10^(22)`
  • In sc, bcc and fcc the ratio of number of atoms per unit cell is given by

    A
    `1:2:3`
    B
    `4:2:1`
    C
    `1:2:4`
    D
    `1:1:3`
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    The volume of atoms (radius r) present in fcc unit cell of metal is :