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Mole fraction of component A in vapour p...

Mole fraction of component `A` in vapour phase is `chi_(1)` and that of component `A` in liquid mixture is `chi_2`, then (`p_(A)^@`)= vapour pressure of pure A, `p_(B)^@` = vapour pressure of pure B), the total vapour pressure of liquid mixture is

A

`p_(A)^@(chi_(2))/(chi_(1))`

B

`p_(A)^@(chi_(1))/(chi_(2))`

C

`p_(B)^@(chi_(1))/(chi_(2))`

D

`p_(B)@^(chi_(2))/(chi_(1))`

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To find the total vapor pressure of the liquid mixture, we can follow these steps: ### Step 1: Understand the Definitions We are given: - \( \chi_1 \): Mole fraction of component A in the vapor phase. - \( \chi_2 \): Mole fraction of component A in the liquid mixture. - \( P_A^0 \): Vapor pressure of pure A. - \( P_B^0 \): Vapor pressure of pure B. ### Step 2: Write the Expression for Partial Pressure of A The partial pressure of component A in the vapor phase can be expressed as: \[ P_A = P_A^0 \cdot \chi_2 \] This equation states that the partial pressure of A is equal to the vapor pressure of pure A multiplied by the mole fraction of A in the liquid phase. ### Step 3: Relate Mole Fraction in Vapor Phase to Total Pressure The mole fraction of A in the vapor phase can also be expressed in terms of the total pressure: \[ \chi_1 = \frac{P_A}{P_{total}} \] From this, we can rearrange to find the total pressure: \[ P_{total} = \frac{P_A}{\chi_1} \] ### Step 4: Substitute the Expression for Partial Pressure of A Now, substitute the expression for \( P_A \) from Step 2 into the equation from Step 3: \[ P_{total} = \frac{P_A^0 \cdot \chi_2}{\chi_1} \] ### Final Expression Thus, the total vapor pressure of the liquid mixture is given by: \[ P_{total} = \frac{P_A^0 \cdot \chi_2}{\chi_1} \]

To find the total vapor pressure of the liquid mixture, we can follow these steps: ### Step 1: Understand the Definitions We are given: - \( \chi_1 \): Mole fraction of component A in the vapor phase. - \( \chi_2 \): Mole fraction of component A in the liquid mixture. - \( P_A^0 \): Vapor pressure of pure A. - \( P_B^0 \): Vapor pressure of pure B. ...
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Knowledge Check

  • Vapour pressure of pure A = 100 torr, moles = 2, vapour pressure of pure B = 80 torr, moles = 3 Total vapour pressure of mixture is

    A
    440 torr
    B
    460 torr
    C
    180 torr
    D
    88 torr
  • Vapour pressure of pure A = 100 torr, moles = 2. Vapour pressure of pure B = 80 torr, moles = 3. Total vapour pressure of mixture is

    A
    440 torr
    B
    460 torr
    C
    180 torr
    D
    88 torr
  • If x_(1) and x_(2) represent the mole fraction of a component A in the vapour phase and liquid mixture respectively and p_(A)^(@) and p_(B)^(@) represent vapours pressures of pure A and pure B. then total vapour pressure of the liquid mixture is

    A
    `(p_(A)^(@)-x_(1))/(x_(2))`
    B
    `(p_(A)^(@)-x_(2))/(x_(1))`
    C
    `(p_(B)^(@)x_(1))/(x_(2))`
    D
    `(p_(B)^(@)x_(2))/(x_(1))`
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