Twenty precent of the surface sites of a catalyst is occupied by nitrogen molecules. The density of surface sites is `6.023xx10^(14)cm^(-2)` . The total sarface area is `1000cm^(2)` . The catalyst is is henced to `300K` and nitrogen is completely desorbed a pressure of `0.001` atm and volume of `2.46cm^(3)` . Calculate the number of sites occupied by niitrogen molecules.
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The correct Answer is:
2
1. Density of sites `=6.023xx10^(14)` Total sites `=6.023xx10^(14)xx1000=6.023xx10^(17)` `20%` sites are occupied. So, sites occupied `=(20)/(100)xx6.023xx10^(17)=12.04xx10^(16)` `PV=nTR` or `n=(0.-001xx2.46xx10^(-3))/(0.0821xx300)=9.98xx10^(-9)` Molecules `=9.98xx10^(-9)xx6.023xx10^(23)=6.02xx10^(16)` Sites occupied per molecules of nitrogen is `("Number of sites")/("Number of molecules")=(12.04xx10^(16))/(6.02xx10^(16))=2`
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20\% of surface sites are occupied by N_(2) molecules. The density of surface site is 6.023xx10^(14)cm^(-2) and total surface area is 1000 cm^(2) . The catalyst is heated to 300 K while N_(2) completely desorbed into a pressure of 0.001 atm and volume of 2.46 cm^(3) . Find the number active sites occupied by each N_(2) molecule.
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