Home
Class 12
CHEMISTRY
300 cm^(3) of an aqueous solution contai...

`300 cm^(3)` of an aqueous solution contains `1.26 g` a polymer. The osmotic pressure of such solution at `300 K` is found to be `1.26xx10^(-3)` bar. Calculate the molar mass of the polymer.

Text Solution

Verified by Experts

`piV=(W_(B))/(Mw_(B))RT`
`Mw_(B)=(W_(B))/(V)xx(RT)/(pi)`
`(1.26)/(0.3)xx(0.083xx300)/(1.26xx10^(-3))`
`=83000 g mol^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Solved Examples|40 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Exercises (Linked Comprehension)|58 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Objective)|9 Videos

  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

200cm^(3) of an aqueous solution contains 1.26g of a polymer. The osmotic pressure of such solution at 300K is found to be 2.57 xx 10^(-3) bar. Calculate the molar mass of the polymer.

200cm^(3) of aqueous solution of pretein contains 1.26 g of the protein. The osmotic pressure of such a soolution at 300 K is found to be 2.57xx10^(-3) bar. Calculater the molar mass of the protein.

Knowledge Check

  • 200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57 xx 10^(-3) bar. The molar mass of protein will be (R = 0.083 L " bar " mol^(-1) K^(-1))

    A
    `51022 g mol^(-1)`
    B
    `122044 g mol^(-1)`
    C
    `31011 g mol^(-1)`
    D
    `61038 g mol^(-1)`

  • 200 mL of an aqueous solution of a protein contains its 1.26 g . The Osmotic pressure of this solution at 300 K is found to be 2.57 xx 10^(-1) bar . The molar mass of protein will be (R = 0.083 L bar mol^(-1)K^(-1) ):

    A
    51022 ` g mol^(-1)`
    B
    122044 `" g mol"^(-1)`
    C
    31011` " g mol"^(-1)`
    D
    61038 ` " g mol"^(-1)`

  • 200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be 2.57 xx 10^(-3) bar. The molar mass of protein will be (R = 0.083 L bar mol^(-1)K^(-1))

    A
    `51022 g mol^(-1)`
    B
    `122044 g mol^(-1)`
    C
    `31011 g mol^(-1)`
    D
    `61038 g mol^(-1)`

    • Similar Questions

    Explore conceptually related problems

    200cm^(3) of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of this solution at 300 K is found to be 2.57xx10^(-3) bar. Calculate the molar mass of the protein.

    200 cm^(3) of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300 K is found to be 2.57 xx10^(-3) bar. Calculate the molar mass of the protein.

    200mL of an aqueus solution of a protien 1.26 g of the protein. The osmotic pressure of such a solution is found to be 2.7xx10^(-3) bar at 300 K. Calculate the molar mass of protein (R=0.083 L bnar mol^(-1)K^(-1))

    Calculate osmotic pressure of 0.1M urea aqueous solution at 300K .

    200 mL of a very dilute aqueous solution of a protein contains 1.9 gm of the protein . If osmotic rise of such a solution at 300K is found to be 38 mm of solution then calculate molar mass of the protein . (Take R = 0.008 L atm mol^(-1) K^(-1) )

    Home
    Profile