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Two miscible liquids A and B having vapo...

Two miscible liquids `A` and `B` having vapour pressure in pure state `P_(A)^(@)` and `P_(B)^(@)` are mixed in mole fraction `chi_(A)` and `chi_(B)` to get a mixtue having total vapour vapour pressure of mixture `P_(M)`. Which of the following relations are correct?

A

`chi_(A)=(P_(M)-P_(B)^(@))/(P_(A)^(@)-P_(B)^(@))`

B

`(chi_(A)(l))/(chi_(A)(V))=P_(M)/P_(A)^(@)`

C

`(chi_(A)(l))/(chi'_(A)(V))=P_(M)/P_(B)^(@)`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
A, B
`P_(M)=P_(A)^(@).chi_(A) + P_(B)^(@).chi_(B)`,`P'=P_(M).chi_(A)(V) = P_(A)^(@).chi_(A)(l)`
`=P_(A)^(@).chi_(A) + P_(B)^(@).(1-chi_(A))`
`:. chi_(A)=(P_(M)-P_(B)^(@))/(P_(A)^(@)-P_(B)^(@))`
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Knowledge Check

  • A mixture of two immiscible liquids A and B , having vapour pressure in pure state obeys the following relationship if chi_(A) and chi_(B) are mole fractions of A and B in vapour phase over the solution

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