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Two miscible liquids A and B having vapo...

Two miscible liquids `A` and `B` having vapour pressure in pure state `P_(A)^(@)` and `P_(B)^(@)` are mixed in mole fraction `chi_(A)` and `chi_(B)` to get a mixtue having total vapour vapour pressure of mixture `P_(M)`. Which of the following relations are correct?

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The correct Answer is:
A, B
`P_(M)=P_(A)^(@).chi_(A) + P_(B)^(@).chi_(B)`,`P'=P_(M).chi_(A)(V) = P_(A)^(@).chi_(A)(l)`
`=P_(A)^(@).chi_(A) + P_(B)^(@).(1-chi_(A))`
`:. chi_(A)=(P_(M)-P_(B)^(@))/(P_(A)^(@)-P_(B)^(@))`
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`{:(,"Column-I",,"Column-II"),((A),"Vapour pressure of binary solution of two miscible and volatile liquids when half of the liquid solution goes into vapour phase",(p),(P_(A)^(@)-P)/(P)=chi_(B)),((B),"Vapour Pressure of two binary miscible and volatile liquids",(q),P_(A)^(@)+P_(B)^(@)),((C),"Vapour pressure of binary solution of two immiscible and volatile liquids",(r),(P_(A)^(@)-P_(B)^(@))chi_(A)+P_(B)^(@)),((D),"Vapour pressure of binary solution having non-volatile solute",(s),sqrt(P_(A)^(@)P_(B)^(@))),(,,(t),"Solution is ideal"):}`

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