Home
Class 12
CHEMISTRY
Given that DeltaT(f) is the depression i...

Given that `DeltaT_(f)` is the depression in freezing point of the solvent in a solution of a non-volatile solute of molarity `m`,the quantity `underset(m rarr0)(Lt) (DeltaT_(f)//m)` is equal to ……………. .

Doubtnut Promotions Banner Mobile Dark

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the relationship between the depression in freezing point (ΔTf), molarity (m), and the freezing point depression constant (Kf) for a non-volatile solute. ### Step-by-Step Solution: 1. **Understand the Formula for Depression in Freezing Point**: The depression in freezing point (ΔTf) is given by the formula: \[ \Delta T_f = K_f \cdot m \cdot i ...
|

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Subjective)|18 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Ex 2.1 (Objective)|10 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Integer)|1 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

Freezing Point Depression: when `15.0 grams` of ethyl alcohol `(C_(2)H_(5)OH)` is dissolved in `750 grams` of formic acid, the freezing point of the solution is `7.20^(@)C`. The freezing point of pure formic acid is `8.40^(@)C` Evalulate `K_(f)` for formic acid.
Strategy: First calculate the molality and the depression of the freezing point. Then solve the equation `DeltaT_(f)=K_(f)m` for `K_(f)` by substituting values for `m` and `DeltaT_(f)`.

Two solutions of non-volatile and non-electrolyte solute `A` and `B` are prepared separately. The molar mass ratio `(M_(A))/(M_(B))=1/3`. Both are prepared as `5%` by weight solution in water. Then what is the ratio of freezing point depresions, `((DeltaT_(f))_(A))/((DeltaT_(f))_(B))` of the solutions?

यदि `DeltaT_(b)` क्वथनांक में उन्नयन तथा m विलयन की मोललता को दर्शाता हो तो सिद्ध कीजिए कि,
`DeltaT_(b)=K_(b)*m`

If all symbols have their usual meaning, then for a non-volatile non-electrolyte solute `Lt_(m rarr 0) ((DeltaT_(f))/(m))` is equal to

Given that Delta T_(f) is the depression in freezing point of the solvent in a solution of a non-volatile solute of molality m, the quantity lim_(m rarr 0)((Delta T_(f))/(m)) is equal to

इकाई मोललता के अवाष्पशील विलेय से बने विलयन में विलायक के हिमांक में अवनमन है, राशि `lim_(m rarr 0) ((DeltaT_(f))/(m))` किसके बराबर होगी?

Consider following figure and answer the questions at the end of it. Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperature and showing elevation in boiling point. Given that DeltaT_(b) is the elevation in boiling point of the solvent in a solution of molality m then underset(mto0)(Lt)((DeltaT_(b))/(m)) is equal to

एक अवाष्पशील विलेय के विलयन (जिसकी मोललता m है) में विलायक के हिमांक में अवनमन `T_(f)` है। तब ` underset(m rarr 0)( Lt) (Delta T_(f)/m)` का मान. ..... के बराबर होगा।

If DeltaT_(f) is the depression in freezing point for the electrolyte and DeltaT_(f)^(@) for the non-electrolyte of the same concentration, then Van't Hoff factor (i) is

Consider following figure and answer the questions at the end of it. Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperature and showing elevation in boiling point. Given that DeltaT_(b) is the elevation in boiling point of the solvent in a solution of molality 'm' then underset(m rarr 0)(Lt) ((Detal T_(b))/(m)) is equal to

Why is freezing point depressed when a non-volatile solute is added to a solvent ?

How are DeltaT_(b) and DeltaT_(f) related to the molar mass of the solute?

Answer the following questions : Why the freezing point depression ( DeltaT_(f) ) of 0.4M NaCl solution is nearly twice than that of 0.4M glucose solution ?