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Gaseous cyclobutane isomerizes to butadi...

Gaseous cyclobutane isomerizes to butadiene in a first order process which has `k` value at `153^(@)C` of `3.3 xx 10^(-4) s^(-1)`. How many minutes would it take for the isomerization to proceeds `40%` to completion at this temperature ?

A

`A. 26 min`

B

`B. 52 min`

C

`C. 13 min`

D

D. None of these

Text Solution

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To solve the problem of how long it takes for gaseous cyclobutane to isomerize to butadiene by 40% at a temperature of 153°C, we will use the first-order kinetics formula. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Given Data - The reaction is first-order. - The rate constant \( k = 3.3 \times 10^{-4} \, \text{s}^{-1} \). - The extent of reaction completion is 40%. ### Step 2: Define the Variables - Let \( A \) be the initial concentration of cyclobutane. We can assume \( A = 100 \) (this is arbitrary and simplifies calculations). - Let \( x \) be the amount of cyclobutane that has reacted. Since the reaction proceeds 40% to completion, \( x = 40 \). - The remaining concentration of cyclobutane will be \( A - x = 100 - 40 = 60 \). ### Step 3: Use the First-Order Kinetics Formula The formula for a first-order reaction is given by: \[ k = \frac{2.303}{t} \log \left( \frac{A}{A - x} \right) \] Substituting the known values into the formula: \[ 3.3 \times 10^{-4} = \frac{2.303}{t} \log \left( \frac{100}{60} \right) \] ### Step 4: Calculate the Logarithm Calculate the logarithm: \[ \log \left( \frac{100}{60} \right) = \log(1.6667) \approx 0.2198 \] ### Step 5: Rearranging the Equation to Solve for Time \( t \) Now, rearranging the equation to solve for \( t \): \[ t = \frac{2.303 \times 0.2198}{3.3 \times 10^{-4}} \] ### Step 6: Calculate \( t \) Calculating the numerator: \[ 2.303 \times 0.2198 \approx 0.506 \] Now substituting back into the equation for \( t \): \[ t \approx \frac{0.506}{3.3 \times 10^{-4}} \approx 1538.79 \, \text{s} \] ### Step 7: Convert Seconds to Minutes To convert seconds to minutes: \[ t \approx \frac{1538.79}{60} \approx 25.65 \, \text{minutes} \] ### Step 8: Rounding to the Nearest Whole Number Rounding \( 25.65 \) to the nearest whole number gives approximately \( 26 \) minutes. ### Final Answer It would take approximately **26 minutes** for the isomerization to proceed 40% to completion at 153°C. ---

To solve the problem of how long it takes for gaseous cyclobutane to isomerize to butadiene by 40% at a temperature of 153°C, we will use the first-order kinetics formula. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Given Data - The reaction is first-order. - The rate constant \( k = 3.3 \times 10^{-4} \, \text{s}^{-1} \). - The extent of reaction completion is 40%. ### Step 2: Define the Variables ...
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Gaseous cyclobutene isomerizes to butadiene in a first order process which has a 'k' value of 3.3xx10^(-4)s^(-1)" at "153^@C . The time in minutes it takes for the isomerization to proceed 40% to completion at this temperature is (Rounded off to the nearest integer)

Gasesous cyclobutane isomerizes to butadiene following first order process which has half life of 150.5 minute at certain temperature. How long will take for the process to occur to the extent of 40% at the same temperature ?

At a given temperature, a first-order reaction has a rate constant of 3.3xx10^(-3)s^(-1) . How much time is required for the reaction to be 75% complete?

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Knowledge Check

  • Gasesous cyclobutane isomerizes to butadiene following first order process which has half life of 150.5 minute at certain temperature. How long will take for the process to occur to the extent of 40% at the same temperature ?

    A
    103 minutes
    B
    121 minutes
    C
    111 minutes
    D
    None of these
  • At a given temperature, a first-order reaction has a rate constant of 3.3xx10^(-3)s^(-1) . How much time is required for the reaction to be 75% complete?

    A
    100 s
    B
    210 s
    C
    420 s
    D
    630 s
  • A first order reaction has specific rate of 10^(-2)s^(-1) . How much time will it take for 20 g of the reactant to reduce to 5 g?

    A
    238.6 s
    B
    138.6s
    C
    346.5 s
    D
    693.0s