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The rate constant of a reaction with a v...

The rate constant of a reaction with a virus is `3.3xx10^(-4)S^(-1)`. Time required for the virus to become `75%` inactivated is

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The correct Answer is:
B

`t_(1//2)=(0.693)/(k)=2100s=35 min`
`t_(75%)=2t_(1//2)=2xx35=70 min`
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प्रथम कोटि अभिक्रिया के लिये दर स्थिरांक` 6.909 min ^(-1)` है। अतः प्रारंभिक अभिकारक को 75% अवक्षेपित होने के लिये मिनिट में आवश्यक समय होगा

ভাইরাসমুক্ত কর্ষণের জন্য এক্সপ্ল্যান্টের প্রয়োজন-

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