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A radioisotope has half life of 10 years...

A radioisotope has half life of 10 years. What percentage of the original amount of it would you expect to remain after 20 years?

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Text Solution

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The correct Answer is:
C
`t_(1//2) = 10` years, `T = 20` year
We know `T = nt_(1//2) implies n = (20)/(10) = 2`
And `N = ((1)/(2))^(n) N_(0)`
`(N)/(N_(0)) = ((1)/(2))^(2) = (1)/(4)`
% of `(N)/(N_(0)) = (1)/(4) xx 100 = 25%`
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