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The equation of a wave is given by Y = A...

The equation of a wave is given by `Y = A sin omega ((x)/(v) - k)`, where `omega` is the angular velocity and `v` is the linear velocity. Find the dimension of `k`.

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To find the dimension of \( k \) in the wave equation \( Y = A \sin \left( \omega \left( \frac{x}{v} - k \right) \right) \), we will use the principle of dimensional homogeneity. Here are the steps to derive the dimension of \( k \): ### Step 1: Understand the Equation The equation of the wave is given as: \[ Y = A \sin \left( \omega \left( \frac{x}{v} - k \right) \right) \] In this equation, \( \omega \) is the angular velocity, \( v \) is the linear velocity, \( x \) is the position, and \( k \) is the term we need to find the dimension for. ...
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Knowledge Check

  • The equation of a wave is given by Y = A sin omega((x)/(v) -k) where omega is the angular velocity and v is the linear velocity. The dimension of k is

    A
    `[LT]`
    B
    `[T]`
    C
    `[T^(-1)]`
    D
    `[T^(2)]`
  • The equation of a wave is given by y = a sin omega [(x)/v -k] where omega is angular velocity and v is the linear velocity . The dimensions of k will be

    A
    `[T^(2)]`
    B
    `[T^(-1)]`
    C
    `[T]`
    D
    `[LT]`
  • The linear velocity of a rotating body is given by v =omega xx r , where omega is the angular velocity and r is the radius vector. The angular velocity of a body omega=hati-2hatj+2hatk and their radius vector r=4hatj-3hatk, |v| is -

    A
    `sqrt(29)` units
    B
    31 units
    C
    `sqrt(37)` units
    D
    `sqrt(41)` units
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