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Two bodies (M) and (N) of equal masses a...

Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.

A

`(k_(1))/(k_(2))`

B

`sqrt((k_(1))/(k_(2)))`

C

`(k_(2))/(k_(1))`

D

`sqrt((k_(2))/(k_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
D
`omega_(1)M=omega_(2)N or (M)/(N) = (omega_(2))/(omega_(1))= sqrt((k_(2))/(k_(1)))" " "as"" "omega = sqrt((k)/(m))`
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  • Two bodies A and B of equal mass are suspended from two separate massless springs of spring constant k_1 and k_2 respectively. If the bodies iscillte vertically such that their maxixum velocities are equal, the ratio of the amplitude of A to that of B is

    A
    `k_1/k_2`
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    `k_2/k_1`
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