Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that pressure is

Options

A. `[(1)/(3)]^(rd)` kinetic energy per unit volume of a gas
B. `[(2)/(3)]^(rd)` kinetic energy per unit volume of a gas
C. `[(3)/(4)]^(rd)` kinetic energy per unit volume of a gas
D. `(3)/(2)xx` kinetic energy per unit volume of a gas

Answer

B

Explanation

According to Kinetic of gases , the pressure exerted by the gas on the walls of container is
`p=p_(0)+p_(1)+p_(2)`
`"i.e " p=p_(0)+(1)/(3)8v^(2)+3gh`
for a container ,
`p_(1)=(1)/(3)rhov^(2)=(1)/(3)(m)/(v).v^(2)xx(2)/(2)`
`(2)/(3)KE[KE=(1)/(2)mv^(2)]`