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Calcium carbonate reacts with aqueous HC...

Calcium carbonate reacts with aqueous HCl to give `CaCl_(2) and CO_(2)` as shows below:
`CaCO_(3)(s)+2HCl (aq) to CaCl_(2)(aq)+CO_(2)(q)+H_(2)O(l)`
In this reaction, 250 mL of 0.76 M HCl reacts with 1000 g of `CaCO_(3)`. Calculate the mass of `CaCl_(2)` formed in the reaction

A

11.1 g

B

10.54 g

C

5.25 g

D

2.45 L

Text Solution

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The correct Answer is:
B
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Calcium carbonate reacts with aqueous HCl to give CaCl_(2) and CO_(2) according to the reaction given below CaCO_(3)(s)+2HCl(aq)rarrCaCl_(2)(aq)+CO_(2)(g)+H_(2)O(l) What mass of CaCl_(2) will be formed when 250mL of 0.76 M HCl reac ts with 1000 g of CaCO_(3) ? Name the limiting reagent. Calculate the number of moles of CaCl_(2) formed in the reaction.

Calcium carbonate reacts with aqueous HCl to give CaCl_(2) and CO_(2) according to the reaction: CaCO_(3)(s)+2HCl(aq) rarr CaCl_(2)(aq)+CO_(2)(g)+H_(2)O(l) What mass of CaCO_(3) is required to react completely with 25 mL of 0.75 M HCl ?

For the reaction : CaCO_(3) (s) hArr CaO (s) + CO_(2) (g)

If 20 g of CaCO_(3) is treated with 100 mL of 20% HCl solution, the amount of CO_(2) produced is

CaCO_(3) + 2HCI to CaCI_(2) + CO_(2) + H_(2)O what will be the amount of CaCI_(2) when 10 g CaCO_(3) mL 0.75 M HCI is used in the reaction ?

Knowledge Check

  • For the reaction : CaCO_(3) (s) hArr CaO (s) + CO_(2) (g)

    A
    `K_(p) =p_((CaCO_(3)))`
    B
    `K_(p) = p(CO_(2))`
    C
    `K_(p) =(1)/(p_((CaCO_(3))))`
    D
    `K_(p)= (1)/(p_((CO_(2))))`

  • If 20 g of CaCO_(3) is treated with 100 mL of 20% HCl solution, the amount of CO_(2) produced is

    A
    `22.4 L`
    B
    `8.80 g`
    C
    `4.40 g`
    D
    `2.24 L`

  • CaCO_(3) + 2HCI to CaCI_(2) + CO_(2) + H_(2)O what will be the amount of CaCI_(2) when 10 g CaCO_(3) mL 0.75 M HCI is used in the reaction ?

    A
    83.25 g
    B
    16.65 g
    C
    11.1 g
    D
    8.325 g
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