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A projectile is fired with a velocity v ...

A projectile is fired with a velocity v at right angle to the slope inclined at an angle `theta` with the horizontal. The range of the projectile along the inclined plane is

A

`(2v^2tantheta)/g`

B

`(v^2sectheta)/g`

C

`(2v^2tanthetasectheta)/g`

D

`(v^2sintheta)/g`

Text Solution

Verified by Experts

The correct Answer is:
C
c. `a_x = -g sin theta, a_y = -g cos theta`
`u_x = 0, u_y = v`
Along y-axis, `S_y = u_yt + 1/2 a_yt^2`

`0 = vt - 1/2 g cos theta t^2`
`t = (2v)/(gcostheta)`
Along x-axis,
`S_x = u_xt+1/2 a_xt^2 - R = 0 xx t -1/2 g sin theta ((2v)/(g soc theta))^2`
`R = (2v^2tanthetasectheta)/(g)` .
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