A small block of mass `M` move on a frictionless surface of an inclimed from as down is figure . The engle of the inclime suddenly change from `60^(@)` to `30^(@)` at point `B` . The block is initally at rest at `A` Assume the collsion between the block and the incline are totally inclassic `(g = 10m//s^(2)`)

The speed of the block at point `B` immedutaly after it strikes the second inclime is -

A small block of mass `M` move on a frictionless surface of an inclimed from as down is figure . The engle of the inclime suddenly change from `60^(@)` to `30^(@)` at point `B` . The block is initally at rest at `A` Assume the collsion between the block and the incline are totally inclassic `(g = 10m//s^(2)`)

The speed of the block at point `B` immedutaly after it strikes the second inclime is -


The speed of the block at point `B` immedutaly after it strikes the second inclime is -

A
`sqrt(60) m//s`
B
`sqrt(45) m//s`
C
`sqrt(30)m//s`
D
`sqrt(15) m//s`
Text Solution
Verified by Experts
The correct Answer is:
B
Between `A` and `B` height fallen by the block is
`h_(1)=sqrt(3)tan60^(@)=3m`
Hence speed of the block just before striking the second incline is
`v_(2)=sqrt(2gh_(1))=sqrt(2xx10xx3)=sqrt(60)m//s`
In perfectly inelastilc collision component of `v_(1)` perpendicular to `BC` will become zero, while component of `v_(1)` parallel of `BC` will remain unchanged.
`v_(2)="component of " v_(1)` along `BC`
`=v_(1)=cos30^(@)=(sqrt(60))((sqrt(3))/2)=(sqrt(45))=m//s`
`h_(1)=sqrt(3)tan60^(@)=3m`
Hence speed of the block just before striking the second incline is
`v_(2)=sqrt(2gh_(1))=sqrt(2xx10xx3)=sqrt(60)m//s`
In perfectly inelastilc collision component of `v_(1)` perpendicular to `BC` will become zero, while component of `v_(1)` parallel of `BC` will remain unchanged.
`v_(2)="component of " v_(1)` along `BC`
`=v_(1)=cos30^(@)=(sqrt(60))((sqrt(3))/2)=(sqrt(45))=m//s`
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