Home
Class 12
CHEMISTRY
An aqueous solution of 2% non volatile s...

An aqueous solution of `2%` non volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molecular mass of the solute ?

Text Solution

Verified by Experts

Relative lowering of vapour pressure `(P_(0)-P_(s))/(P_(0))=(n_(s))/(n_(0))`
`P_(0)=1.013" bar",P_(s)=1.004" bar"`
w = 2 gms W = 98 gms
M = 18 m = ?
`(1.013-1.004)/(1.013)=(2xx18)/(m xx98)`
`m=(2xx18xx1.013)/(0.009xx98)=(36xx1.013)/(0.882)`
`=41.35" gms"//"mole".`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise INTEXT QUESTIONS|10 Videos

  • SOLUTIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise SHORT ANWER QUESTIONS|23 Videos

  • SOLID STATE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise INTEXT QUESTIONS|27 Videos

  • SURFACE CHEMISTRY

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise INTEXT QUESTIONS|8 Videos

Similar Questions

Explore conceptually related problems

What is the normal boiling point of the solution represented by the phase diagram ?

The vapour pressure of 4% solution of a non-volatile solute in water at 100^@C is 745 mm. What is the molecular weight of solute?

Knowledge Check

  • 6 g. of a non volatile solute is dissolved in 90g. of water, such that the lowering in vapour pressure is 2%. The molecular weight of the solute is

    A
    65
    B
    92
    C
    60
    D
    80

  • Vapour pressure of an aqueous solution is 2% less than that of the solvent. The molality of the solution is

    A
    2m
    B
    1.5 m
    C
    1.13 m
    D
    0.2 m

  • Vapour pressure of an aqueous solution is 2% less than that of the solvent . The molality of the solution is

    A
    2m
    B
    1.5m
    C
    1.13m
    D
    0.2m

    • Similar Questions

    Explore conceptually related problems

    The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53" K kg mol"^(-1) .

    Vapour pressure of pure water at 27^@C is 3000kPa. By dissolving 5g of a non volatile molecular solid in 100g of water the vapour pressure is decreased to 2985 k pa. What is the molecular weight of solute ?

    Assertion:When dry air is passed continuously through an aqueous solution of non-volatile solute, vapour pressure of solution decreases gradually. Reason: Some air absorbed in the solution.

    300 mL of an aqueous solution of a protein contains 2.52 g of the protein. If osmotic pressure of such a solution at 300 K is 5.04xx10^(-3) bar, the molar mass of the protein in g mol^(-1) is

    The osmatic of solution containing non-volatile, non electrolyte solute is 7.6 atm at 27^(@)C then the boiling point of the same solution is _(Assume that molality and molarity are same)

    Home
    Profile