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The radius of the first electron orbit o...

The radius of the first electron orbit of a hydrogen atom is `5.3 xx 10^(-11)m`. What is the radius of the second orbit ?

Text Solution

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`r_(n)prop n^(2)`
`(r_(2))/(r_(1))=(2^(2))/(1^(2))=(4)/(1) rArr r_(2)=4r_(1)`
`therefore r_(2)=4xx5.3xx10^(-11)=2.12xx10^(-10)m`.
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Knowledge Check

  • The radius of the second Bohr orbit is

    A
    0.053 nm
    B
    0.106 nm
    C
    0.212 nm
    D
    0,0265 nm

  • The energy of an electron in the first Bohr's orbit of a hydrogen atom is -2.18 xx 10^(-18)J . Its energy in the second orbit would be

    A
    `-1.09 xx 10^(-18)J`
    B
    `-4.36 xx 10^(-18)J`
    C
    `-5.45 xx 10^(-18)J`
    D
    `-8.72 xx 10^(-18)J`

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