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Calculate the number of electrons in a s...

Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of `10.0 g`. Silver has 47 electrins per atom, and its molar mass is `107.87 gmol^(-1)`.

Text Solution

Verified by Experts

The correct Answer is:
`2.62xx10^(24)`
Number of atoms in 10g of silver is
`n=(6.023xx10^(23)xx10)/(107.87)=5.58xx10^(22)`
Number of electrons is `47n=2.62xx10^(24)`.
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Find the number of electrons present in an 8-g gold pin . Given : Molar mass of gold =197 g/mol , electron per atom is gold =79 and Avogadro's number =6.023xx10^23 g^(-1) mol^(-1)

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Knowledge Check

  • If 965 coulombs of electricity is passed through a metal cup dipped in silver(l) salt solution, in order to plate it with silver. Then the amount of silver deposited on its surface is (Given : the molar mass of Ag = 108 g mol^(-1), 1F = 96500 coulombs)

    A
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    B
    `1.002 g`
    C
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    D
    `9.89 g`

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