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The capacitance of a capacitor becomes 4...

The capacitance of a capacitor becomes `4//3` times its original value if a dielectric slab of thickness `t=d//2` is inserted between the plates (d is the separation between the plates). What is the dielectric constant of the slab?

Text Solution

Verified by Experts

The correct Answer is:
2
(6) `(epsilon_(0)A)/(d-d/2+d/(2k))=4/3(epsilon_(0)A)/d)`. Solve to get `k=2`.
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