100 cells each of emf 5V and internal resistance `1 Omega` are to be arranged to produce maximum current in a `25 Omega` resistance. Each row contains equal number of cells. Find the number of rows.

Explanation

To solve the problem of arranging 100 cells, each with an emf of 5V and an internal resistance of 1Ω, to produce maximum current in a 25Ω resistance, we will follow these steps:

### Step-by-Step Solution:

1. **Understand the Arrangement of Cells**:
We have 100 cells, and we need to arrange them in rows such that each row has an equal number of cells. Let the number of rows be \( N \). Therefore, the number of cells in each row will be \( \frac{100}{N} \).

2. **Calculate the Internal Resistance of One Row**:
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