Home
Class 12
PHYSICS
A ray of light is incident on a glass sp...

A ray of light is incident on a glass sphere of refractive index `3//2` . What should be the angle of incidence so that the ray which enters the sphere does not comme out of the sphere?

A

`tan^(-1)(2//3)`

B

`60^(@)`

C

`90^(@)`

D

`30^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the angle of incidence at which a ray of light strikes a glass sphere with a refractive index of \( \frac{3}{2} \) such that it does not exit the sphere after entering. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have a glass sphere with a refractive index \( n = \frac{3}{2} \). - We need to find the angle of incidence \( I \) such that the light ray, after entering the sphere, does not exit. 2. **Critical Angle Calculation**: - For total internal reflection to occur, the angle of incidence at the boundary must be greater than the critical angle \( \theta_C \). - The critical angle can be calculated using the formula: \[ \sin \theta_C = \frac{1}{n} \] - Substituting the refractive index: \[ \sin \theta_C = \frac{1}{\frac{3}{2}} = \frac{2}{3} \] 3. **Finding the Critical Angle**: - To find \( \theta_C \), we take the inverse sine: \[ \theta_C = \sin^{-1}\left(\frac{2}{3}\right) \] 4. **Applying Snell's Law**: - When the ray enters the sphere, we apply Snell's law at the point of incidence: \[ n_1 \sin I = n_2 \sin \theta_T \] - Here, \( n_1 = 1 \) (air), \( n_2 = \frac{3}{2} \), and \( \theta_T \) is the angle of refraction inside the sphere. - Rearranging gives: \[ \sin I = \frac{3}{2} \sin \theta_T \] 5. **Condition for Total Internal Reflection**: - For the ray to not exit the sphere, the angle \( \theta_T \) must equal \( \theta_C \). - Therefore, substituting \( \theta_T = \theta_C \): \[ \sin I = \frac{3}{2} \sin \theta_C \] - Since \( \sin \theta_C = \frac{2}{3} \): \[ \sin I = \frac{3}{2} \cdot \frac{2}{3} = 1 \] 6. **Finding the Angle of Incidence**: - The only angle for which \( \sin I = 1 \) is: \[ I = 90^\circ \] ### Conclusion: The angle of incidence \( I \) should be \( 90^\circ \) for the ray of light to enter the glass sphere and not come out.

To solve the problem, we need to determine the angle of incidence at which a ray of light strikes a glass sphere with a refractive index of \( \frac{3}{2} \) such that it does not exit the sphere after entering. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have a glass sphere with a refractive index \( n = \frac{3}{2} \). - We need to find the angle of incidence \( I \) such that the light ray, after entering the sphere, does not exit. ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Assertion-Reasoninig|2 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Linked Comprehension|51 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Subjective|26 Videos
  • FRICTION

    CENGAGE PHYSICS|Exercise QUESTION BANK|1 Videos
  • GRAVITATION

    CENGAGE PHYSICS|Exercise Question Bank|39 Videos

Similar Questions

Explore conceptually related problems

A ray of light is incident on a glass sphere of refractive index 3/2. What should be the angle of incidence so that the ray which enters the sphere does not come out of the sphere ?

A ray of light in incident on a glass sphere of refractive index 3//2 . What should be the angle of incidence so that the ray which enters the sphere does not come out of the sphere ?

A ray of unpolarised light is incident on a glass plate of refractive index 1.54 at polarising angle, then angle of refraction is :

Unpolarized light is incident on a plane glass surface. What should be the angle of incidence so that the reflected and refracted rays are perpendicular to eachother ?

A ray of light falls on a glass plate of refractive index mu=1.5 . What is the angle of incidence of the ray if the angle between the reflected and refracted rays is 90^@ ?

A ray of light is incident on the surface of plate of glass of refractive index 1.5 at the polarising angle. The angle of refraction of the ray will be

A horizontal ray of light is incident on a solid glass sphere of radius R and refractive index mu . What is net deviation of the beam when it emerged from the other side of the sphere?

A ray of light suffers minimum deviation when incident on an equilateral prism of refractive index sqrt2 . What is the angle of incidence ?

A ray of light is incident on a glass slab at an angle of 45^(@) . If refractive index of glass be 1.6, what is the angle of refraction ?

A ray of light is incident on a glass slab of refractive index 1.5, making an angle of 40^(@) with the surface. The angle of refraction in glass is

CENGAGE PHYSICS-GEOMETRICAL OPTICS-Single Correct
  1. Critical angle of glass is theta(1) and that of water is theta(2). The...

    Text Solution

    |

  2. Light is incident normally on face AB of a prism as shown in Figure. A...

    Text Solution

    |

  3. A ray of light is incident on a glass sphere of refractive index 3//2 ...

    Text Solution

    |

  4. Two identical glass (mu(g)=3//2) equiconvex lenses of focal length f a...

    Text Solution

    |

  5. An object is kept at a distance of 16 cm from a thin lens and the imag...

    Text Solution

    |

  6. Point object O is placed on the principal axis of a convex lens of foc...

    Text Solution

    |

  7. Light of wavelength 500nm traveling with a speed of 2.0xx10^(8)ms^(-1)...

    Text Solution

    |

  8. A hollow double concave lens is made of very thin transparent materia...

    Text Solution

    |

  9. The velocity of light in a medium is half its velocity in air. If a ra...

    Text Solution

    |

  10. A convex lens of focal length 20cm and a concave lens of focal length ...

    Text Solution

    |

  11. An equiconvex lens is made from glass of refractive index 1.5. If the ...

    Text Solution

    |

  12. An object is put at a distance of 5cm from the first focus of a convex...

    Text Solution

    |

  13. A luminous object is placed 20 cm from surface of a convex mirror and ...

    Text Solution

    |

  14. Consider the situation shown in figure. Water (mu=4//3) is filled in a...

    Text Solution

    |

  15. Refraction takes place at a convex spherical boundary separating glass...

    Text Solution

    |

  16. The image of point P when viewd from top of the slabs will be

    Text Solution

    |

  17. The refractive index of a prism is 2. The prism can have a maximum ref...

    Text Solution

    |

  18. One of the refracting surfaces of a prism of angle 30^(@) is silvered...

    Text Solution

    |

  19. Angle of minimum deviation is equal to the angle of prism A of an equi...

    Text Solution

    |

  20. A plano-convex lens fits exactly into a plano-concave lens. Their plan...

    Text Solution

    |