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In Young's double-slit experiment, two w...

In Young's double-slit experiment, two wavelengths of light are used simultaneously where `lambda_(2) = 2 lambda_(1)`. In the fringe pattern observed on the screen,

A

maxima of wavelength `lambda_(2)` can coincide with minima of wavelength `lambda_(1)`

B

fringe width of `lambda_(2)` will be double that of fringe width of `lambda_(1)` and nth order maxima of `lambda_(2)` will coincide with 2nd order maxima of `lambda_(1)`

C

nth order minima of `lambda_(2)` will coincide with 2th order minima of `lambda_(1)`

D

none of above

Text Solution

Verified by Experts

The correct Answer is:
b.,c

`beta_(2) = (lambda_(2) D)/(d) = 2 (lambda_(1))/(d) D`
as `beta_(1) = (lambda_(1))/(d) D`
nth order maxima of `lambda_(2)` coincides with 2th order maxima of `lambda_(1)`. `n^(th)` order minima of `lambda_(2)` does not coincide with 2th order maxima of `lambda_(1)`.
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Knowledge Check

  • In young's double slit experiment, if wavelength of light changes from lambda_(1) to lambda_(2) and distance of seventh maxima changes from d_(1) to d_(2) . Then

    A
    `(d_(1))/(d_(2)) = (lambda_(1))/(lambda_(2))`
    B
    `(d_(1))/(d_(2)) = (lambda_(2))/(lambda_(1))`
    C
    `(d_(1))/(d_(2)) = (lambda_(1^(2)))/(lambda_(2^(2)))`
    D
    `(d_(1))/(d_(2)) = ((lambda_(2))/(lambda_(1)))^(2)`
  • In a Young's double slit experiment, (slit distance d) monochromatic light of wavelength lambda is used and the fringe pattern observed at a distance D from the slits. The angular position of the bright fringes are

    A
    ` "sin"^(-1)((N lambda)/(d))`
    B
    ` "sin"^(-1)(((N+(1)/(2)) lambda)/(d))`
    C
    ` "sin"^(-1)((N lambda)/(D))`
    D
    ` "sin"^(-1)(((N+(1)/(2)) lambda)/(D))`
  • In a Young's double-slit experiment, if the incident light consists of two wavelengths lambda_(1) and lambda_(2) , the slit separation is d, and the distance between the slit and the screen is D, the maxima due to each wavelength will coincide at a distance from the central maxima, given by

    A
    `(lambda_(1)+lambda_(2))/(2Dd)`
    B
    LCM of `(lambda_(1))/(d)` and `(lambda_(2)D)/(d)`
    C
    `(lambda_(1)-lambda_(2))(2D)/(d)`
    D
    HCF of `(lambda_(1)D_(2))/(d)` and `(lambda_(2)D)/(d)`
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