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Calculate the binding energy for nucleon...

Calculate the binding energy for nucleon of .`_6^(12) C` nucleus, if mass of proton `m_p = 10078 u`, mass of neutron `m_n = 1.0087 u` , mass of `C_12, m_C =12.0000 u`, and `1 u =931 .4 MeV`.

Text Solution

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In the nucleus of carbon, there are `6` protons and `6` neutrons.
Now,
`6 m_(p) = 6(1.0078) =6.0468 u`
`6m_(n) =6(1.0087) =6.05224 u`
Total mass `=6 m_(p) + 6m_(n) =12.0990 u `
`m_(c) =12.000 u `
Mass defect, `Delta m =0.0990 u`
`BE = Delta m xx 931.4 = (0.0990)931.4`
`92.2 MeV` .
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