A charged particle of mass 5 mg and charge `q= +2 mu C` has velocity `vec v = 2 hat i - 3 hat j + 4 hat k.` Find out the magnetic force on the charged particle and its acceleration at this instant due to magnetic field `vec B = 3 hat j - 2 hat k. vec v and vec B` are in `ms^-1 and Wbm^-2` , respectively.

Explanation

`vecF=qvecvxxvecB=2xx10^-6(2hati-3hatj+4hatk)xx(3hatj-2hatk)`
`=2xx10^-6[-6hati+4hatj+6hatk]N`
By Newton's law of motion,
`veca=(vecF)/m=(2xx10^-6)/(5xx10^-6)(-6hati+4hatj+6hatk)`
`=0.8(-3hati+2hatj+3hatk) ms^-2`