The average value of current i=I(m) sin ...

The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega )` to `t=(3 pi)/(2 omega)` si how many times of `(I_m)`?

Text Solution

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The correct Answer is:

`gt i lt =(int_(pi//2 omega)^(3pi//2omega) I_(m) sin omega t dt)/((3 pi)/(2omega)-(pi)/(2 omega)) = (I_(m)(-(cos omegat)/(omega))_(pi//2omega)^(3 pi//2omega))/((pi)/(omega))=0`.

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r.m.s. value of current i=3+4 sin (omega t+pi//3) is:

`sqrt17A`

`(5)/(sqrt2)A`

`(7)/(sqrt2)A`

The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

`(2I_(0))/pi`

`2I_(0)`

`(4I_(0))/pi`

`I_(0)/pi`

The average value of a.c. voltge E =E_(0) sin omega t over the time interval t = 0 to t = pi//omega is

`- 2 E_(0)//pi`

`E_(0)//pi`

`(2 E_(0))/(pi)`

zero