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When an ac source of emfe=E(0) sin (100 ...

When an ac source of emf`e=E_(0) sin (100 t)` is connected across a circuit, the phase difference between emf e and currnet I in the circuit is observed to be `(pi)//(4)` as shown in fig. If the circuit consists possibly only of R-C or R-C of L-R series, find the relationship find the relationship between the two elements.

A

`R=1 kOmega, C=10 (mu)F`

B

`R=1 kOmega, C=1(mu)F`

C

`R=1 kOmega,L=10H`

D

`R=1 kOmega, L=H`

Text Solution

Verified by Experts

The correct Answer is:
A
Since currents leads emf, therefore, this is an R-C circuit.
`tan phi=(X_(C )-X_(L))/(R ) here phi=45^(@)`
`:. X_(C )=R` [`X_(L)=0` as there is no inductor]
`(1)/(omega C)=R`
L.H.S `=(1)/(100 xx 10 xx 10^(-6)) = R = (10^3) Omega`.
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Knowledge Check

  • When an AC source of emf e=E_(0) sin(100t) is connected across a circuit i in the circuit, the phase difference between the emf e and the current i in the circuit is observed to be (pi//4) , as shown in the diagram. If the circuit consists possibly only of R-C or R-L or L-C in series, find the relationship between the two elements

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