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Let bar a= hat i+ hat j+ hat k ,""b=...

Let ` bar a= hat i+ hat j+ hat k ,""b= hat i- hat j+2 hat k` and ` bar c=x hat i+(x-2) hat j- hat k` . If the vector c lies in the plane of a and b , then x equals (1) 0 (2) 1 (3) `-4` (4) `-2`

Text Solution

Verified by Experts

`a,b,c` are in simple plane
`[abc]=0`
`[[x,x-2,-1],[1,1,1],[1,-1,2]]=0`
`x(2+1)-(x-2)1+(-1)(-2)=0`
`3x-x+2+2=0`
`2x+4=0`
`x=-2`
option`4=(-2)`
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