Power radiated by a black body is `P_0` and the wavelength corresponding to maximum energy is around `lamda_0`, On changing the temperature of the black body, it was observed that the power radiated becames `(256)/(81)P_0`. The shift in wavelength corresponding to the maximum energy will be

Options

A. `+(lamda_0)/(4)`
B. `+(lamda_0)/(2)`
C. `-(lamda_0)/(4)`
D. `-(lamda_0)/(2)`

Answer

C

Explanation

According to Wien's law `gamma_0T_0=lamdaT`
According to Stefan's law `(P_0)/(P)=((T_0)/(T))^4`
As `P=(256)/(81)P_0implieslamda=(3)/(4)lamda_0`
Wavelength shift`Deltalamda=lamda-lamda_0=-(lamda_0)/(4)`