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The decreasing valuse of bond angles fro...

The decreasing valuse of bond angles from `NH_(3) (106^(@))` to `SbH_(3)(101^(@))` down group -15 of the periodic table is due to .

A

Decreasing lp-lp repulsion

B

Decreasing electronegativity

C

Increasing bp-bp repulsion

D

Decreasing p-orbital character in `sp^(3)` .

Text Solution

Verified by Experts

The correct Answer is:
B
Due to decrease in `EN` the bond pair moves away hence repulsion will be less from `NH_(3)` to `SbH_(3)` .
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Knowledge Check

  • The decreasing value of bond angles from NH_(3)(106^(@)) to SbH_(3)(101^(@)) down group-15 of the periodic table is due to

    A
    decreasing ip-bp repulsion
    B
    decreasing electronegativity
    C
    increasing bp-bp repulsion
    D
    inreasing p-orbital character in `sp^(3)`

  • The dercreasing valuers of bond angles from NH_3 (106^@) to SbH_3 ( 101^@) down the group 15 of the peridic table is due to :

    A
    increase in bp-bp repulsion
    B
    increase in p-orbital character in `sp^3`
    C
    decrease in-pp repulsion
    D
    decrease in electrongativity

  • The decreasing order of bond angles from NH_(3) (107^(@)) to SbH_(3)(91.3^(@)) down the group 15 elements is due to :

    A
    increasing bond pair : bond pair repulsion
    B
    increasing p-orbital character on `sp^(3)` orbital
    C
    decreasing lone pair- bond pair repulsion
    D
    decreasing electronegativity.

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