The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What is the circumference of benzene ring ? Bond length between single and double bonds `= 1.4 Å` .

Options

A. `(3 xx 1.54 + 3 xx 1.33) Å`
B. `(4 xx 1.54 + 2 xx 1.33) Å`
C. `(6 xx 1.4)Å`
D. `(4 xx 1.33 +2 xx 1.54)Å`

Explanation

To find the circumference of a benzene ring, we need to consider the bond lengths of the carbon-carbon bonds in the ring. Benzene has a resonance structure that averages the bond lengths between single and double bonds.

### Step-by-Step Solution:

1. **Identify the number of carbon atoms in benzene**:
Benzene (C₆H₆) has 6 carbon atoms arranged in a ring.

2. **Determine the bond lengths**:
- The bond length of a carbon-carbon single bond (C-C) is given as 1.54 Å.
- The bond length of a carbon-carbon double bond (C=C) is given as 1.33 Å.
- The bond length between single and double bonds (the average bond length in benzene) is given as 1.4 Å.

3. **Understand the structure of benzene**:
Benzene has alternating single and double bonds, but due to resonance, all the C-C bonds in benzene are equivalent and can be considered to have a bond length of 1.4 Å.

4. **Calculate the total bond length in the benzene ring**:
Since there are 6 carbon-carbon bonds in the benzene ring, we can calculate the total circumference by multiplying the bond length by the number of bonds:
\[ \text{Circumference} = \text{Number of bonds} \times \text{Average bond length} = 6 \times 1.4 \, \text{Å} \]

5. **Perform the calculation**:
\[ \text{Circumference} = 6 \times 1.4 = 8.4 \, \text{Å} \]

### Final Answer:
The circumference of the benzene ring is **8.4 Å**.