Based on `VSEPR` theory the number of `90^(@) F -Br -F` angles in a molecules of `BrF_(5)` is_____.

Answer

8

Explanation

Hybridisation of Br in `brF_(5) = (1)/(2) (7 +5) =6 =sp^(3) d^(2)` Geometry `=OH`
Due to one lp of `e^(-')s` it has square pyrmidal shape
It has eight `(F -Br-F)` bonds which are at `90^(@)` There are
(1) `F^(1) -Br -F^(2)` (2) `F^(2)-Br -F^(3)` (3) `F^(3) -Br -F^(4)`
(4) `F^(4) -Br -F^(1)` (5) `F^(1) -Br -F^(5)` (6) `F^(5) -Br -F^(4)`
(7) `F^(5) -Br -F^(3)` (8) `F^(5) -Br -F^(2)`
.