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H2O2 is reduced rapidly by Sn^(2+). H2O2...

`H_2O_2` is reduced rapidly by `Sn^(2+). H_2O_2` is decomposed slowly at room temperature to yeild `O_2` and `H_2O_2`. `136g` of `10%` by mass of `H_2O_2` in water is treated with `100mL` of `3M Sn^(2+)` and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are:
`2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2)`
`2H_(2)O_(2)to2H_(2)O+O_(2)`
The equivalent of `H_2O_2` reacted with `Sn^(2+)` is

A

`0.2`

B

`0.3`

C

`0.4`

D

`0.6`

Text Solution

Verified by Experts

The correct Answer is:
D
The problem can be solved simply by mole concept since `n` factor for both `H_(2)O_(2)` and `Sn^(2+)is 2`.
`2H^(o+)+underset( "1 mole")(H_(2)O_(2))+underset(1 mol)(Sn^(2+))toSn^(4+)+2H_(2)O` ltMbrgt mmol of `H_(2)O_(2)`= mmol of `Sn^(2+)` ltbRgt `=100 mLxx3M=300 mmol`
`=300mmol of H_(2)O_(2)`
`=600 m Eq=0.6 Eq`
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Knowledge Check

  • H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) The equivalent of H_2O_2 left after reacting with Sn^(2+) is

    A
    `0.1`
    B
    `0.2`
    C
    `0.3`
    D
    `0.4`

  • H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) The volume strength of H_2O_2 left after reacting with Sn^(2+)

    A
    `1.12 V`
    B
    `11.2 V`
    C
    `2.24 V`
    D
    `22.4 V`

  • H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) Calculate the volume of O_2 produced at 27^@C and 1 atm after H_2O_2 is reacted with Sn^(2+) and the mixture is allowed to stand.

    A
    `2.46 L`
    B
    `4.92 L`
    C
    `1.23 L`
    D
    `7.38 L`

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