What is the molarity of `H_2O_2` of the `11.2V` (volume strength)?

Explanation

To find the molarity of hydrogen peroxide (H₂O₂) with a volume strength of 11.2, we can follow these steps:

### Step 1: Understand Volume Strength
Volume strength refers to the volume of oxygen gas (O₂) that can be liberated by one volume of the solution at standard conditions. For hydrogen peroxide, 1 volume strength corresponds to the release of 1 volume of O₂.

### Step 2: Relate Volume Strength to Normality
From the information given, we know that:
- 5.6 volume strength corresponds to 1 normality (N) of H₂O₂.
- Therefore, we can establish a relationship:
\[ \text{Normality (N)} = \frac{\text{Volume Strength}}{5.6} \]

### Step 3: Calculate Normality
Using the volume strength of 11.2:
\[ \text{Normality (N)} = \frac{11.2}{5.6} = 2 \, \text{N} \]

### Step 4: Relate Normality to Molarity
The relationship between molarity (M) and normality (N) is given by:
\[ \text{Molarity (M)} = \frac{\text{Normality (N)}}{n} \]
where \( n \) is the number of equivalents. For H₂O₂, the n factor is 2 because it can donate two moles of electrons.

### Step 5: Calculate Molarity
Substituting the values we have:
\[ \text{Molarity (M)} = \frac{2 \, \text{N}}{2} = 1 \, \text{M} \]

### Conclusion
The molarity of H₂O₂ with a volume strength of 11.2 is **1 mol/L**.

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