Boron always forms covalent compound.
The small size of `B^(3+)` favours formation of covalent compound.

Options

A. If both `(A)` are correct and `( R)` is the correct explanation of `(A)`.
B. If both `(A)` and `( R)` are correct but `( R)` is not the correct explanation of `(A)`.
C. If `(A)` is correct, but `( R)` is incorrect.
D. If `(A)` is incorrect, but `( R)` is correct.

Answer

A

Explanation

The sum of `IE_(1) + IE_(3)` for `B` is very high and `B^(3+)` ion is not known and boron always forms covalent compounds.