Boron always forms covalent compound. ...

Boron always forms covalent compound.
The small size of `B^(3+)` favours formation of covalent compound.

If both `(A)` are correct and `( R)` is the correct explanation of `(A)`.

If both `(A)` and `( R)` are correct but `( R)` is not the correct explanation of `(A)`.

If `(A)` is correct, but `( R)` is incorrect.

If `(A)` is incorrect, but `( R)` is correct.

Verified by Experts

The correct Answer is:

The sum of `IE_(1) + IE_(3)` for `B` is very high and `B^(3+)` ion is not known and boron always forms covalent compounds.

P-BLOCK GROUP 13 - BORON FAMILY
CENGAGE CHEMISTRY|Exercise Exercise (Integer)|9 Videos
P-BLOCK GROUP 13 - BORON FAMILY
CENGAGE CHEMISTRY|Exercise Exercise (Fill In The Blanks)|17 Videos
P-BLOCK GROUP 13 - BORON FAMILY
CENGAGE CHEMISTRY|Exercise Exercise (Single Correct)|86 Videos
ORGANIC REACTION MECHANISM
CENGAGE CHEMISTRY|Exercise Analytical and Descriptive|6 Videos
P-BLOCK GROUP 14 - CARBON FAMILY
CENGAGE CHEMISTRY|Exercise Exercises Archives (Subjective)|9 Videos

Assertion. Boron always forms covalent compounds. Reason. The small size of B^(3+) favours formation of covalent bonds.

If both assertion and reason are true, and reason is the true explanation of the assertion.

If both assertion and reason are true, but reason not is the true explanation of the assertion.

If assertion is true, but reason is false.

If both assertion and reason are false.

If both assertion and reason are true and the reason is the correct explanation of teh assertion.

If both assertion and reason are true but reason in not the correct explation of the assertion.

If assertion is true but reason is false.

If assertion is false but reason is true.

Both A and R are true and R is the correct explanation of A

Both A and R are true but R is not a correct explanation of A

A is true but R is false

A is false but R is true