Home
Class 11
CHEMISTRY
Identify(A) based on followihng facts : ...

Identify(A) based on followihng facts :
a. `A` reduces `HgCl_(2)` solution to white ppt. charging to grey .
b. (A) turns ` FeCl_3` yellow colured solution to green .
c. (A) givewhite pot, with `NaOH` soluble ine xcess fo `NaOH` . ltrgt d. (A) gives yellow dirty ppt. on passing `H_2S` gs , soluble in yellow ammium sulpjde (YAS).
e. (A) gives chromyl chloride test .

Text Solution

Verified by Experts

(A) gives yellow dirty ppt . Soluble in `YAS`.
`rArr` (A) has `Sn^(2+)`
(A) gives chromyl chromyl chloride test `(of Cl^(Θ))`
`rArr` (A) has ` Cl^(Θ)`
` rarr` (A) is `SnCl_2`
Explanation :
a. `SnCl_2 + 2HgCl_2 rarr underset ("White ppt .") (Hg_2Cl_2 narrr) + Sncl_4`
`SnCl_2 + Hg_2Cl_2 rarr underset (Grey) + SnCl_4`
b. `underset ("Yellow") (2FeCl_3) + SnCl_2 rarr underset (Green) (2FeCl_2) + SnCl_4`
c.`SnCl_2 + 2NaOH rarrr underset ("White" ) (Sn (OH)_2) narr +2 NaCl`
` Sn(OH)_2 + 2NaOH rarr underset(("Soluble")) underset ("Sodium stannate ") (Na_2SnO_2 + 2H_2O)`
d. `SnCl_2 + H_2S rarr 2 HCl + underset ("Yellow") ("SnS narr")`
`SnS + (NH_4)_2 underset ((YAS)) (S_2) rarr (NH_4)_3 underset("Soluble") (SnS_3)`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY|Exercise Ex (Subjective)|21 Videos
  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY|Exercise Ex (Objective)|19 Videos
  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Subjective)|9 Videos
  • P-BLOCK GROUP 13 - BORON FAMILY

    CENGAGE CHEMISTRY|Exercise Exercise Archives (Subjecive)|9 Videos
  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Exercises (Archives )Subjective|4 Videos

Similar Questions

Explore conceptually related problems

Identify (A) based on the following facts: a. (A) redues HgCI_(2) solution to white ppt changing to grey b.(A) turn FeCI_(3) yellow coloured solution to green c. (A) gives while ppt NaOH soluble in excess of NaOH d. (A) gives yellow dirty ppt ,on passing H_(2)S gas in yellow ammonium salphide (YAS) e. (A) gives chromyl chloride test

Colourless salt (A) decolouriese la solution and gives whte ppt. (changing toblack) with AgNO_(3) solution. (A) also changes FeCl_(2) (yellow) solution to FeCl2 (green). Identify (A) and explain reactions.

Knowledge Check

  • Which set gives yellow ppt.?

    A
    `KO_(3),Sb_(2)S_(3),CdS`
    B
    `Sb_(2)S_(3),CdS,PbCrO_(4)`
    C
    `PbCrO_(4),As_(2)S_(3),SnS_(2)`
    D
    `SnS_(2),As_(2)S_(3),PbCrO_(4),PbO`
  • Aqueous solution of BaBr_(2) , gives yellow ppt with

    A
    `K_(2)CrO_(4)`
    B
    `AgNO_(3)`
    C
    both
    D
    none
  • A very dilute acidic solution of Cd^(2+) and Ni^(2+) gives only yellow ppt. of CdS on passing H_(2)S , this is due to

    A
    Solubility product `(K_(sp))` of CdS is more than that of NiS
    B
    Solubility product `(K_(sp))` of CdS is less than that of NiS
    C
    `Cd^(2+)` belong to IIB group while `Ni^(2+)` belongs to `IV^(th)` group
    D
    CdS is insoluble in yellow ammonium sulphide (YAS)
  • Similar Questions

    Explore conceptually related problems

    (A) (colourless solution ) gives white ppt (B) with NaOH solution but ppt dissolves in excess of NaOH forming (C ) (C ) does not give ppt with H_(2)S but on boiling with NH_(4)CI while ppt (B) appears (A) also gives yellow ppt with AgNO_(3) identify (A),(B) and (C )

    Which compound gives yellow ppt.with iodine and alkali ?

    An inorganic salt in its aqueous solution produced a white ppt. with NaOH which dissolves in excess of NaOH. Also its aqueous solution produced light yellow ppt., with AgNO_(3) sparingly soluble in NH_(4)OH . The probable salt is

    Which of the following gives yellow ppt. with H_2PtCl_6 ?

    Which of the following ppt. is soluble in both aqua regia and sodium disulphide (yellow)?