`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.

Options

A. `3d_(xy)^(1),3d_(yz)^(1),3d_(zx)^(1)`
B. `3d_(xy)^(1),3d_(yz)^(1),3d_(z2)^(1)`
C. `3d_((x^(2)-y^(2)))^(1)3d_(z^(2))^(1),3d_(xz)^(1)`
D. `3d_(xy)^(1),3d_((x^(2)-y^(2)))^(1),3d^(1)xz`

Answer

A

Explanation

magnetic momnet indicates that there are three unpaired electrons present in chromium These must be present in lower energy orbitals which are `3d_(xy) 3d_(yx)` and `3d_(xz)` .