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As shown in the figure, M is a man of ma...


As shown in the figure, M is a man of mass 60 kg standing on a block of mass 40 kg kept on ground. The co-efficient of friction between the feet of the man and the block is 0.3 and that between B and the ground is 0.1. If the man accelerates with an acceleration `2(m)/(s^2)` in the forward direction, then,

A

it is not possible

B

B will move backwards with an acceleration `0.5(m)/(s^2)`

C

B will not move

D

B will move forward with an acceleration `0.5(m)/(s^2)`.

Text Solution

Verified by Experts

The correct Answer is:
B

The friction force acting between the man and the block is :
`F_f=60xx20=120N`
and not `0.3xx60xx10=180N`
F.B.D. of B:
Acceleration of `B=(120-100)/(40)=0.5(m)/(s^2)` (backward)
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