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With respect to a rectangular Cartesian ...

With respect to a rectangular Cartesian coordinate system, three vectors are expressed as
`vec(a)= 4hat(i)-hat(j), vec(b)= -3hat(i)+2hat(j) and vec(c )= -hat(k)`
Where, `hat(i), hat(j), hat(k)` are unit Vector, along the X, Y and Z-axis respectively. The unit vectors `hat(r )` along the direction of sum of these vector is

A

`vec(r )= 1/(sqrt(3))(hat(i)+hat(j)-hat(k))`

B

`vec(r )= 1/(sqrt(2))(hat(i)+hat(j)-hat(k))`

C

`vec(r )= 1/3(hat(i)-hat(j)+hat(k))`

D

`vec(r )= 1/(sqrt(2))(hat(i)+hat(j)+hat(k))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the unit vector \(\hat{r}\) along the direction of the sum of the given vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we will follow these steps: ### Step 1: Write down the vectors The vectors are given as: \[ \vec{a} = 4\hat{i} - \hat{j} \] \[ \vec{b} = -3\hat{i} + 2\hat{j} \] \[ \vec{c} = -\hat{k} \] ### Step 2: Sum the vectors We will sum the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\): \[ \vec{R} = \vec{a} + \vec{b} + \vec{c} \] Substituting the values: \[ \vec{R} = (4\hat{i} - \hat{j}) + (-3\hat{i} + 2\hat{j}) + (-\hat{k}) \] ### Step 3: Combine like terms Now, we will combine the components along each axis: - For \(\hat{i}\) components: \(4 - 3 = 1\) - For \(\hat{j}\) components: \(-1 + 2 = 1\) - For \(\hat{k}\) components: \(0 - 1 = -1\) Thus, we have: \[ \vec{R} = 1\hat{i} + 1\hat{j} - 1\hat{k} \] ### Step 4: Write the resultant vector The resultant vector can be expressed as: \[ \vec{R} = \hat{i} + \hat{j} - \hat{k} \] ### Step 5: Find the magnitude of the resultant vector The magnitude of \(\vec{R}\) is given by: \[ |\vec{R}| = \sqrt{(1)^2 + (1)^2 + (-1)^2} = \sqrt{1 + 1 + 1} = \sqrt{3} \] ### Step 6: Find the unit vector \(\hat{r}\) The unit vector \(\hat{r}\) in the direction of \(\vec{R}\) is given by: \[ \hat{r} = \frac{\vec{R}}{|\vec{R}|} = \frac{\hat{i} + \hat{j} - \hat{k}}{\sqrt{3}} \] ### Final Answer Thus, the unit vector \(\hat{r}\) along the direction of the sum of the vectors is: \[ \hat{r} = \frac{1}{\sqrt{3}}\hat{i} + \frac{1}{\sqrt{3}}\hat{j} - \frac{1}{\sqrt{3}}\hat{k} \] ---

To find the unit vector \(\hat{r}\) along the direction of the sum of the given vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), we will follow these steps: ### Step 1: Write down the vectors The vectors are given as: \[ \vec{a} = 4\hat{i} - \hat{j} \] \[ ...
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Knowledge Check

  • If vec(a)=4hat(i)-hat(j),vec(b)=-3hat(i)+2hat(j)and vec(c)=-hat(k). Then the unit vector hat( r) along the direction of sum of these vectors will be

    A
    `hat(r)=(1)/(sqrt3)(hat(i)+hat(j)-hat(k))a`
    B
    `hat(r)=(1)/(sqrt2)(hat(i)+hat(j)-hat(k))`
    C
    `hat(r)=(1)/(3)(hat(i)-hat(j)+hat(k))`
    D
    `hat(r)=(1)/(sqrt2)(hat(i)+hat(j)+hat(k))`
  • The angle which the vector vec(A)=2hat(i)+3hat(j) makes with the y-axis, where hat(i) and hat(j) are unit vectors along x- and y-axis, respectively, is

    A
    `cos^(-1)(3//5)`
    B
    `cos^(-1)(2//3)`
    C
    `tan^(-1)(2//3)
    D
    `sin^(-1)(2//3)`
  • If vec(P)=hat(i)+hat(j)-hat(k) and vec(Q)=hat(i)-hat(j)+hat(k) , then unit vector along (vec(P)-vec(Q)) is :

    A
    `(1)/(sqrt(2))hat(i)-(1)/(2)hat(k)`
    B
    `(sqrt(2)hat(j)-sqrt(2)hat(k))/(2)`
    C
    `(hat(j)-hat(k))/(2sqrt(2))`
    D
    `(2hat(j)-2hat(k))/(4)`
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