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Two stones are thrown up simultaneously ...

Two stones are thrown up simultaneously from the edge of a cliff with initial speed `v and 2 v`. The relative position of the second stone with respect to first varies with time till both the stones strike the ground as.

A

linearly

B

first linearly then parabolically

C

parabolically

D

first parabolically then linearly
(assume that the first stone comes to rest after striking the ground).

Text Solution

Verified by Experts

The correct Answer is:
B
Initially when both are in air, the relative acceleration between them is zero. Therefore, relative position versus-time graph is a straight line. Once the first ball reaches the ground, its acceleration becomes zero. Therefore, the relative acceleration is now `g` and the graph is parabolic.
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