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A square of side a and uniform thickness...

A square of side `a` and uniform thickness is divided into four equal parts. If upper right part is removed, then find the coordinates of centre of mass of remaining part.
.

A

`((5)/(12)a, (5)/(12)a)`

B

`((7)/(12)a, (7)/(12)a)`

C

`((1)/(4)a, (1)/(4)a)`

D

`((1)/(3)a, (1)/(3)a)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Let mass of each is `m`. Coordinates of their respective centre of masses are shown in figure.
`x_(cm) = (m (a)/(4) + m(3a)/(4) + m(a)/(4))/(m + m + m) = (5a)/(12)`
`x_(cm) = (m (a)/(4) + m(a)/(4) + m(3a)/(4))/(m + m + m) = (5a)/(12)`.
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Knowledge Check

  • A square of side 4cm and uniform thickness is divided into four squares. The square portion A^'AB^'D is removed and the removed portion is placed over the portion DB^'BC^' . The new position of centre of mass is

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