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The velocity of centre of mass of the sy...

The velocity of centre of mass of the system remains constant, if the total external force acting on the system is.

A

minimum

B

maximum

C

unity

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
(d) When the total external force acting on the system is zero, the velocity of centre of mass remains constant.
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Velocity Of Centre Of Mass Of System

The velocity (in m/s) of centre of mass of the system as shown in the figure is :

The concept of centre of mass proves that laws of mechanics which are true for a point mass, are equally valid for all macroscopic bodies of any shape, size, mass, etc. For example, when vector sum of external forces acting on a system of particles is zero, the velocity of centre of mass of the system will remain constant. Read the above passage and answer the following questions : (i) Is centre of mass of a body a real point ? (ii) Does centre of mass lie within the body always ? (iii) How do you justify that overset rarr(v_(cm)) = constant ?

A system consists of two particles. At t=0 , one particle is at the origin, the other, which has a mass of 0.60kg , is on the y-axis at y=80m . At t=0 , the centre of mass of the system is on the y-axis at y=24m and has a velocity given by (6.0m//s^3)t^2hatj . (a) Find the total mass of the system. (b) Find the acceleration of the centre of mass at any time t. (c) Find the next external force acting on the system at t=3.0s .

The magnitude of acceleration of centre of mass of the system is

Knowledge Check

  • If no external force acts on a system

    A
    (a) velocity of centre of mass remains constant
    B
    (b) position of centre of mass remains constant
    C
    (c) acceleration of centre of mass remains non-zero and constant
    D
    (d) All of the above

  • If net external force acting on the system is zero then

    A
    Velocity of the individual particle of the system will remain constant
    B
    Velocity of the center of mass of the system will remain constant
    C
    Velocity of the center of mass of the system will be zero
    D
    Velocity of the individual particle of the system will be zero

  • The velocity (in m/s) of centre of mass of the system as shown in the figure is :

    A
    `(2 [1 + (4)/(sqrt2)] hat(i) + 8 [(1)/(sqrt2) + 2 ] hat(j))/(7)`
    B
    `(2 [1 + (4)/(sqrt2)] hat(i) + 8 [(1)/(sqrt2) - 2 ] hat(j))/(7)`
    C
    `(2 [1 + (4)/(sqrt2)] hat(i) - 8 [(1)/(sqrt2) + 2 ] hat(j))/(7)`
    D
    `(8 [(1)/(sqrt2) - 2] hat(i) + 2 [1 + (4)/(sqrt2] hat(j)])/(7)`
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