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A body of mass 10kg starting from rest, ...

A body of mass `10kg` starting from rest, accelerates uniformly to a speed of `30m//s` in `10s`. Brakes are applied and the body stops in next `5 seconds`, (figure). Calculate the accelerating force and the stopping force

Text Solution

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Here, `m=10kg, u=0, v=30m//s, t= 10s`
`a=(v-u)/t=(30-0)/10= 3m//s^(2)`
`:.` Accelerating force, `F=ma = 10xx3= 30N`
In the second part, `u=30m//s, v=0, t= 5s`
`a=(v-u)/t= (0-30)/5 = -6m//s^(2)`
`:.` Retarding force `F= ma =10(-6)= -60N`.
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