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A bullet of mass 0.04 kg moving with a s...

A bullet of mass 0.04 kg moving with a speed of `90 ms^(-1)` enters a heavy wooden block and is stooped after a distance of 60 cm . What is the average resistive force exerted by the block on the bullet ?

Text Solution

AI Generated Solution

To solve the problem of finding the average resistive force exerted by the block on the bullet, we can follow these steps: ### Step 1: Identify the given values - Mass of the bullet, \( m = 0.04 \, \text{kg} \) - Initial speed of the bullet, \( u = 90 \, \text{m/s} \) - Final speed of the bullet, \( v = 0 \, \text{m/s} \) (since it comes to a stop) - Distance traveled in the block, \( s = 60 \, \text{cm} = 0.6 \, \text{m} \) ...
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Knowledge Check

  • A bullet of mass 40g moving with a speed of 90ms^(-1) enters a heavy wooden block and is stopped after a direction of 60cm. The average resistive force exered by the block on the bullet is

    A
    180N
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    400 N
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  • A bullet of mass 0.04 kg moving with a speed of 600 m/s penetrates a heavy wooden block. It stops after a penetration of 500 cm. The resistive force exerted by the block on the bullet is

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