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Two particles of masses m(1) and m(2) mo...

Two particles of masses `m_(1) and m_(2)` move with velocities `upsilon_(1) and upsilon_(2)` towards eachother on a smooth horizontal surface. What is the velocity of their centre of mass ?

Text Solution

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`overset rarr(v_(cm)) = (m_(1) overset rarr(v_(1)) + m_(2) overset rarr(v_(2)))/(m_(1)+ m_(2))`
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Knowledge Check

  • Two bodies of masses 2 kg and 4 kg are moving with velocities 2 m s^(-1) and 10 m s^(-1) towards each other due to mutual gravitational attraction. What is the velocity of their centre of mass?

    A
    `5.3 m s^(-1)`
    B
    `6. 4 m s^-1`
    C
    zero
    D
    `8 . 1 m s^-1`
  • Two bodies of masses 2kg and 4 kg are moving with velocities 20 m/s and 10m/s towards each other due to mutual gravitational attraction . What is the velocity of their centre of mass ?

    A
    `5.3 "ms"^(-1)`
    B
    `6.4 "ms"^(-1)`
    C
    Zero
    D
    `8.1"ms"^(-1)`
  • Two bodies of different masses 2kg and 4kg are moving with velocities 2m//s and 10m//s towards each other due to mutual gravitational attraction. Then the velocity of the centre of mass is

    A
    `5 ms^(-1)`
    B
    `6 ms^(-1)`
    C
    `8 ms^(-1)`
    D
    zero
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