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The oxidation states of the most electro...

The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` are

A

`0 `and `-1`

B

`-1` and `-2`

C

`-2 `and `0`

D

`-2`and `-1`

Text Solution

Verified by Experts

The correct Answer is:
B

Oxygen in `H_(2)O_(2)` and `BaSO_(4)` (formed) has `-1` and `-2`ox.no. respectively.
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P BAHADUR-REDOX REACTIONS-Exercise 3(A) Objective problems
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  2. When SO(2) is passed through an acidified K(2)Kr(2)O(7) solution, the ...

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  11. One mole of N(2)H(4) loses ten moles of electrons to form a new compou...

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  12. Number of electron involved in the reduction of Cr(2)O(7)^(2-) ion in ...

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  14. The number of electrons lost in the following change is Fe+H(2)Orarr...

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  15. The oxidation number of C in HNC is

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  16. Oxidation number of Cl in NOClO(4) is:

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  17. Oxidation number of S in [(CH(3))(2)SO] is:

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  18. The equivalent weight of salt KHC(2)O(4).H(2)C(2)O(4).4H(2)O when us...

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  19. The oxidation number of Cl in CaOCl(2) is

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  20. Oxidation number of carbon in carbon sub-oxide is:

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