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The oxidation states of the most electro...

The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` are

A

`0 `and `-1`

B

`-1` and `-2`

C

`-2 `and `0`

D

`-2`and `-1`

Text Solution

Verified by Experts

The correct Answer is:
B
Oxygen in `H_(2)O_(2)` and `BaSO_(4)` (formed) has `-1` and `-2`ox.no. respectively.
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Knowledge Check

  • The oxidation states of the most electronegative element in the products of the reaction betweeen BaO_(2) with dil H_(2)SO_(4) are

    A
    `-1`
    B
    `+1`
    C
    `-2`
    D
    0

  • The oxidation state of the most electronegative element in the products of the reaction between BaO_2 and H_2SO_4 are

    A
    0 and-1
    B
    -1 and-2
    C
    -2and0
    D
    -2and+l

  • The oxidation states of the most elecrtronegative element in the products of rection between BaO^(2) and diluent H_(2)SO_(4) are:

    A
    `-1`
    B
    `+1`
    C
    `-2`
    D
    0

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